b^2-10b-29=-5

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Solution for b^2-10b-29=-5 equation:


Simplifying
b2 + -10b + -29 = -5

Reorder the terms:
-29 + -10b + b2 = -5

Solving
-29 + -10b + b2 = -5

Solving for variable 'b'.

Reorder the terms:
-29 + 5 + -10b + b2 = -5 + 5

Combine like terms: -29 + 5 = -24
-24 + -10b + b2 = -5 + 5

Combine like terms: -5 + 5 = 0
-24 + -10b + b2 = 0

Factor a trinomial.
(-2 + -1b)(12 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(12 + -1b)' equal to zero and attempt to solve: Simplifying 12 + -1b = 0 Solving 12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1b = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1b = 0 + -12 -1b = 0 + -12 Combine like terms: 0 + -12 = -12 -1b = -12 Divide each side by '-1'. b = 12 Simplifying b = 12

Solution

b = {-2, 12}

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